KClKCl has a lattice energy of −701 kJ/mol.−701 kJ/mol. Consider a generic salt, ABAB , where A2+A2+ has the same radius as K+,K+, and B2−B2− has the same radius as Xl−.Xl−. Estimate the lattice energy of the salt ABAB .

Respuesta :

Explanation:

It is given that lattice energy is -701 kJ/mol.

Whereas it is known that realtion between lattice energy and radius is as follows.

               Lattice energy [tex]\propto \frac{Z_{+}Z_{-}}{r}[/tex]

where,          [tex]Z_{+}[/tex] = +2,    and [tex]Z_{-}[/tex] = -2

Therefore, lattice energy of AB = [tex]4 \times \text{lattice energy of KCl}[/tex]

                                                    = [tex]4 \times -701 kJ/mol[/tex]

                                                    = -2804 kJ/mol

Thus, we can conclude that lattice energy of the salt ABAB is -2804 kJ/mol.

The lattice energy of the salt AB is -2804 kJ/mol where as KCl has a lattice energy of −701 kJ/mol.

What is lattice energy?

The difference in energy between the expected experimental value for the energy of the ionic solid and the actual value observed.

It is given that lattice energy is -701 kJ/mol.

Whereas it is known that the relation between lattice energy and radius is as follows.

Lattice energy [tex]\propto[/tex] [tex]\frac{Z_+Z_-}{r}[/tex]

Where,  [tex]Z_+ =[/tex] +2, [tex]Z_-[/tex]= -2

Therefore, lattice energy of AB = 4 X Lattice energy of KCl

= 4 X - 701 kJ/mol.

= -2804 kJ/mol

Thus, we can conclude that the lattice energy of the salt AB is -2804 kJ/mol.

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