Answer:
1019.27 g.
Explanation:
- For the balanced reaction:
2Na + Cl₂ → 2NaCl,
It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.
- Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:
2 moles of Na need → 1 mol of Cl₂, from the stichiometry.
57.5 moles of Na need → ??? mol of Cl₂.
∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na = (1 mol)(57.5 mol)/((2 mol) = 28.75 mol.
∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) = (28.75 mol)(35.453 g/mol) = 1019.27 g.
