Answer:
2.21 moles of HCl are present in 1.2 L of a 1.84 M HCl solution
Explanation:
Molarity (M),
Molality (m),
Normality (N),
Mass %,
Parts per million(ppm), billion(ppb), thousands(ppt)
are some of the terms we use to represent the concentration of the solution that is to represent the amount of solute present in a solvent.
Molarity is moles of solute present in 1L of the solution.
The formula to find Molarity is
[tex]Molarity = \frac {(moles solute)}{(volume of solution in L) }[/tex] and its unit is mol/L
Rearranging the formula
We get
moles = Molarity × Volume
Plugging in the values
[tex]moles=1.84M \times 1.2L (M=mol/L)[/tex]
[tex]=1.84 mol/L\times1.2L=2.21 moles[/tex] (Answer)
