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An office has 7 male employees and 8 female employees. The manager randomly chooses 2 employees to attend a football game. What is the probability that the Manger chooses 2 female employees

Respuesta :

Answer:

47%

Step-by-step explanation:

8+7=15

7/15=47%

The probability of choosing [tex]2[/tex] females to attend football game is equal to [tex]\frac{8}{15}[/tex].

What is probability?

" Probability is defined as the ratio of number of favourable outcomes to the total number of outcomes."

Formula used

Probability [tex]= \frac{n(F)}{n(T)}[/tex]

[tex]n(F) =[/tex] Number of favourable outcomes

[tex]n(T)=[/tex] Total number of outcomes

According to the question,

Given,

Number of females in the office [tex]=8[/tex]

Number of males in the office [tex]=7[/tex]

Therefore,

Total number of employees in the office [tex]= 15[/tex]

Number of employees chooses to attend a football game [tex]= 2[/tex]

Condition: Manger chooses 2 female employees

Substitute the value in the formula to get the probability of choosing [tex]2[/tex] females to attend football game we get,

Required probability [tex]= \frac{8}{15}[/tex]

Hence, the  probability of choosing [tex]2[/tex] females to attend football game is equal to [tex]\frac{8}{15}[/tex].

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