Respuesta :
Answer:
500-W
Explanation:
A heater is a type of a resistor.
The power dissipated by the circuit is not directly proportional to the resistance offered.
The expression for power and resistance is:
[tex]P=\frac {V^2}{R}[/tex]
From the above formula, it is clear that the power is inversely proportional to the resistance.
Hence, when the heaters are connected in series (The resistance is doubled) , the power reduced to half.
So, total power = 1000 - W /2 = 500-W
The total power used by the two heaters when they are connected in series with a single ac voltage of 120 V is 500 Watts
What is power?
This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:
Power (P) = voltage (V) × current (I)
P = IV
Power = square voltage (V²) / resistance ®
P = V² / R
Assumption
- Let the initial power for 1 heater (P₁) = 1000 Watts
- Initial resistance for 1 heater ( R₁) = R
- New resistance for 2 heaters (R₂) = 2R (since they are in series)
- New power for 2 heaters (P₂) =?
How to determine the new power of the heaters
P = V² / R
Cross multiply
PR = V²
Since the voltage is constant, we have
P₁R₁ = P₂R₂
1000 × R = P₂ × 2R
Divide both side by 2R
P₂ = 1000R / 2R
P₂ = 500 Watts
Thus, the total power used by the two heaters is 500 Watts
Learn more about electrical power:
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