Respuesta :
Answer:
16.67 % ( approx )
Step-by-step explanation:
Let x be the charge at hotel P,
Since, the charge at Hotel P is 25 percent less than the charge at Hotel R,
That is, (100-25)% of charge at hotel R = charge at hotel P
75% of charge at hotel R = x
⇒ Charge at hotel R = [tex]\frac{100x}{75}[/tex] = [tex]\frac{4x}{3}[/tex],
The charge at Hotel P is 10 percent less than the charge at Hotel G
(100-10)% of charge at hotel G = charge at hotel P
90% of charge at hotel G = x
⇒ Charge at hotel G = [tex]\frac{100 x}{90}[/tex] = [tex]\frac{10x}{9}[/tex],
[tex]\because \frac{\frac{4x}{3}-\frac{10x}{9}}{\frac{4x}{3}}\times 100[/tex]
[tex]=\frac{\frac{12x-10x}{9}}{\frac{4x}{3}}\times 100[/tex]
[tex]=\frac{\frac{2x}{9}}{\frac{4x}{3}}\times 100[/tex]
[tex]=\frac{1}{6}\times 100[/tex]
[tex]=\frac{100}{6}[/tex]
[tex]\approx 16.67\%[/tex]
Hence, the charge for a single room at Hotel R is approximately 16.67 % greater than the charge for a single room at Hotel G.
