Answer:
600 mL
Explanation:
The volume of 10% acid solution used to make the mixture = 200 L
Let the volume of 30% acid solution used to make the mixture = x mL
Total volume of the mixture = (200+ x) mL
For 10% acid solution:
C₁ = 10% , V₁ = 200 mL
For 30% acid solution :
C₂ = 30% , V₂ = x mL
For the resultant solution of sulfuric acid:
C₃ = 25% , V₃ = (200 + x) mL
Using
C₁V₁ + C₂V₂ = C₃V₃
10×200 + 30×x = 25×(200 + x)
Solving for x,
x = 600 mL
600 milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume.
