Answer:[tex]a=1.25\times 10^6 m/s^2[/tex]
Explanation:
Given
initial velocity of bullet[tex]\left ( u\right )=500 m/s[/tex]
Penetration distance[tex]\left ( x\right )=10cm[/tex]
i.e. bullet will finally stop after moving 10cm in the sandbag
Final velocity of Bullet[tex]\left ( v\right )=0[/tex]
Using motion of equation to get acceleration
[tex]v^2-u^2=2ax[/tex]
[tex]0-\left ( 500\right )^2=2\left ( -a\right )\left ( 0.1\right )------\left ( - because\ it\ is\ deceleration\right )[/tex]
[tex]a=\frac{\left ( 500\right )^2}{2\times 0.1}[/tex]
[tex]a=1.25\times 10^6 m/s^2[/tex]
