A light, rigid rod is 63.3 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at rest with a small, massive ball attached to its bottom end. You strike the ball, suddenly giving it a horizontal velocity so that it swings around in a full circle. What minimum speed at the bottom is required to make the ball go over the top of the circle?

Respuesta :

Answer:

v = 4.98 m/s

Explanation:

As the massive ball is attached to the end of the rod

Now the ball will move in vertical circle such that it will just complete the vertical circle

So at the top position of its motion the velocity of ball must be zero

now we can use mechanical energy conservation as we know that there is no friction force here

[tex]\frac{1}{2}mv^2 = mgh[/tex]

[tex]\frac{1}{2}mv^2 = mg(2L)[/tex]

[tex]\frac{1}{2}m(v^2) = m(9.81)(2\times 0.633)[/tex]

[tex]v^2 = 2(9.81)(2\times 0.633)[/tex]

[tex]v = 4.98 m/s[/tex]