Answer:
10 liters of the 1% solution and 8 liters of the 10% solution she should mix to make the 5% solution.
Explanation:
Let the volume of 1% acid solution used to make the mixture = x L
So, the volume of 10% acid solution used to make the mixture = y L
Total volume of the mixture = x + y = 18 L .................. (1)
For 1% acid solution:
C₁ = 1% , V₁ = x L
For 10% acid solution :
C₂ = 10% , V₂ = y L
For the resultant solution of sulfuric acid:
C₃ = 5% , V₃ = 18 L
Using
C₁V₁ + C₂V₂ = C₃V₃
1×x + 10×y = 5×18
So,
x + 10y = 90 .................. (2)
Solving 1 and 2 we get,
x = 10 L
y = 8 L
Thus,
10 liters of the 1% solution and 8 liters of the 10% solution she should mix to make the 5% solution.
Answer:
1% = 10 liters 10% solution=5 liters
Explanation:
We have found that she should mix x=10 liters of the 1% solution with y=8 liters of the 10% solution to get 18 liters of the desired 5% solution.
