Answer:
Keiko should mix 20 mL 1% solution and 80 mL 6% solution for to make 100 mL 5% solution
Explanation:
There are 2 unknown values X= mL 6% solution and Y=1% solution. So, we need 2 equations:
1. Equation acid concentration. X mL 6% + Y mL 1% = 100 mL 5%
2. Equation solvent concentration X mL 94% + Y mL 99% = 100 mL 95%
When clearing X and Y :
(X mL 6% + Y mL 1% = 100 mL 5%) (-15,7)
X mL 94% + Y mL 99% = 100 mL 95%
_______________________________
- Y 0.83 = 16.5
Y = 19.9 mL 1% solution
Replace Y in anyone equation and X = 80 mL 6% solution
I hope to see been helpful
20 ml of the 1% solution and 80 ml of the 6% solution should she mix to make the 100 ml of 5% solution
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. Concentration shows the amount of solute in a unit of the amount of solvent.
Molarity (M)
Molarity shows the number of moles of solute in every 1 liter of solution.
[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = volume of the solution
For molarity a mixture can be formulated :
[tex]M_{mix}=\frac{total\:mole}{total\:volume}[/tex]
[tex]M_{mix}=\frac{M1.V1+M2.V2}{V1+V2}[/tex]
Keiko needs 100 mL of a 5% acid solution
The available solutions are 1% and 6%
We can make a mathematical equation from the two statements above
The total volume of the 1% and 6% solutions is 100 ml
5% = 1% .V1 + 6% .V2 /( V1 + V2 )
5% = 1% .V1 + 6% .V2 / 100
5 = 1% .V1 + 6% .V2 or
500 = V1 + 6V2
Equations 1 and 2 we do elimination and substitution
500 = V1 + 6V2
100 = V1 + V2
----------------------- -
400 = 5V2
V2 = 80 ml
V1 = 20 ml
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Keywords: reaction coefficients, potassium carbonate, electrolytes
