Answer:
Factor the sum of 27u^3+64 is (3u+4)(9u^2-12u+16)
Option B is correct.
Step-by-step explanation:
We are given:
27u^3+64
It can be written as:
(3u)^3+(4)^3
The formula used for a^3+b^3 is
a^3 + b^3 = (a+b)(a^2-ab+b^2)
here a = 3u and b = 4
Putting values and finding answer:
(3u)^3+(4)^3 =(3u+4)((3u)^2-(3u)(4)+(4)^2)
(3u)^3+(4)^3 =(3u+4)(9u^2-12u+16)
So, Factor the sum of 27u^3+64 is (3u+4)(9u^2-12u+16)
Option B is correct.
