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A photograph has a length that is 2 inches longer than it’s width, x. So it’s area is given by the expression x(x+2) square inches. If the area of the photograph is 48 square inches, what is the width of the photograph

Respuesta :

TheBreeze

The equation will look something like this:

x(x+2) = 48

Distribute the x:

x^2 + 2x = 48

Subtract both sides by 48:

x^2 + 2x - 48 = 0

(x+8)(x-6) = 0

x = -8 and x = 6

Since you can't have a negative width, the only plausible answer is 6 inches.

asuwafohjames

The width of the photograph is 6 cm.

To calculate the width of the photography, we use the formula below.

Formula:

  • A = x(x+2)............ Equation 1

Where:

  • A = Area
  • x = width

From the question,

Given:

  • A = 48 in²

Substitute this value into equation 1

  • 48 = x(x+2)
  • x²+2x = 48

Using completing the square to solve the quadratic equation,

  • x²+2x+(1)² = 48+1
  • (x+1)² = 49
  • x+1 = ±√49
  • x+1 = ±7

Eithere

  • x +1 = +7
  • x = 7-1
  • x = 6 cm

Or

  • x+1 = -7
  • x = -7-1
  • x = -8

Hence, The width of the photograph is 6 cm.

Learn more about area here: https://brainly.com/question/24487155

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