Answer:
0.115 kg
Explanation:
Since no energy is transferred to the surroundings, all the heat from the copper is used to melt the block of ice. So we can write:
[tex]m_c C_c \Delta T_c = m_i \lambda_i[/tex]
where:
[tex]m_c = 200.0 g = 0.2 kg[/tex] is the mass of the copper
Cc = 385 J/kg•°C is the specific heat of copper
[tex]\Delta T = 500^{\circ}C-0^{\circ}C=500^{\circ}[/tex] is the change in temperature of the copper (the copper stops to give heat to the ice when they are in thermal equilibrium, so when they have reached the same temperature)
[tex]m_i[/tex] is the mass of ice
[tex]\lambda_i = 334 kJ /kg = 3.34\cdot 10^5 J/kg[/tex] is the latent heat of fusion of ice
Solving the equation for the mass of the ice, we find
[tex]m_i = \frac{m_c C_c \Delta T_c}{\lambda_i}=\frac{(0.2)(385)(500)}{3.34\cdot 10^5}=0.115 kg[/tex]
