Respuesta :

C and D
x^2 - 4x + 4 = (x-2)^2
x^2 + 10x +25 = (x+5)^2

Answer:

C. [tex]x^2 - 4x + 4[/tex]

D. [tex]x^2 +10x +25[/tex]

Step-by-step explanation:

A trinomial [tex]ax^2+bx+c[/tex] is perfect square trinomial if,

[tex]D=b^2 - 4ac = 0[/tex],

A. [tex]x^2 -9[/tex]

By comparing,

a = 1, b = 0, c = -9,

[tex]0^2 - 4\times 1\times -9\neq 0[/tex]

⇒ it is not a perfect square trinomial.

B. [tex]x^2 -100[/tex]

By comparing,

a = 1, b = 0, c = -100,

[tex]0^2 - 4\times 1\times -100\neq 0[/tex]

⇒ it is not a perfect square trinomial.

C. [tex]x^2 - 4x + 4[/tex]

By comparing,

a = 1, b = -4, c = 4,

[tex](-4)^2 - 4\times 1\times 4=16-16=0[/tex]

it is a perfect square trinomial.

D. [tex]x^2 +10x +25[/tex]

By comparing,

a = 1, b = 10, c = 25,

[tex]10^2 - 4\times 1\times 25=100-100=0[/tex]

it is a perfect square trinomial.

E.  [tex]x^2 +15x + 36[/tex]

By comparing,

a = 1, b = 15, c = 36,

[tex]15^2 - 4\times 1\times 36=225-144=81\neq 0[/tex]

⇒ it is not a perfect square trinomial.