Answer:
0.113 m/s²
Explanation:
Acceleration due to an object's gravity is:
g = GM / R²
where G is the universal gravitational constant (6.67×10⁻¹¹ m³/kg/s²),
M is the mass of the object,
and R is the distance from the object's center of mass.
Given M = 1.08×10²⁰ kg and R = 2.52×10⁵ m:
g = (6.67×10⁻¹¹ m³/kg/s²) (1.08×10²⁰ kg) / (2.52×10⁵ m)²
g = 1.13×10⁻¹ m/s²
The acceleration of gravity on the surface of Enceladus is 0.113 m/s².
