Answer:
[tex]\%\;of \;water = 36.08\%[/tex]
Explanation:
Molecular mass of [tex]CuSO_4.5H_2O = 249.72\;g/mol[/tex]
Molecular mass of [tex]H_2O = 18.02\;g/mol[/tex]
In [tex]CuSO_4.5H_2O[/tex], 1 mole of compound has 5 moles of [tex]H_2O[/tex].
Mass of 5 moles of [tex]H_2O = No.\; of\;mole\;of\;water \times\;molecular\;mass\;of\;water[/tex]
Mass of 5 moles of [tex]H_2O = 5\times 18.02 = 90.10\;g/mol[/tex]
[tex]\%\;of \;water=\frac{Mass\;of\;water}{Tolat\;mass\;of\;CuSO_4}[/tex]
[tex]\%\;of \;water = \frac{90.10}{249.72}\times 100= 36.08\%[/tex]
