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An aircraft, traveling northward, lands on a runway with a speed of 77 m/s. Once it touches down, it slows to 6.3 m/s over 705 m of runway. What is the average acceleration (magnitude and direction) of the plane during landing (in m/s2)

Respuesta :

Answer:

magnitude

[tex]a = 4.18 m/s^2[/tex]

Direction

Opposite to the velocity of aircraft

Explanation:

As we know that the initial speed of the aircraft when it land on the ground is

[tex]v_i = 77 m/s[/tex]

now the final speed of the aircraft when it covers 705 m on runway is given as

[tex]v_f = 6.3 m/s[/tex]

so here we know that

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

so now we can say that

[tex]6.3^2 - 77^2 = 2ad[/tex]

[tex]6.3^2 - 77^2 = 2(a)(705)[/tex]

[tex]a = -4.18 m/s^2[/tex]

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