Answer:
(A) 800 K (B) 2.4 KW
Explanation:
We have given the COP =1.6
The sink temperature [tex]T_L=300K[/tex]
We have to find the source temperature, that is [tex]T_H[/tex]
(A) We know that COP of the heat pump is given by [tex]COP=\frac{T_H}{T_H-T_L}[/tex]
So [tex]1.6=\frac{T_H}{T_H-300}[/tex]
[tex]1.6T_H-480=T_H[/tex]
[tex]0.6T_H=480[/tex]
[tex]T_H=800K[/tex]
(B) We have given the work done =1.5 KW
The rate of heat transfer is given by [tex]Q_H=COP\times W=1.6\times 1.5=2.4KW[/tex]
