[tex]\huge\boxed{\text{48 inches}}[/tex]
We know that [tex]\frac{\text{length}}{\text{width}} = \frac{60}{\text{width}} = \frac{5}{4}[/tex].
Solve using cross multiplication of the last two fractions. I will use [tex]w[/tex] to represent the width of the rectangle. [tex]60*4=w*5[/tex]
Multiply. [tex]240=5w[/tex]
Divide both sides of the equation by [tex]5[/tex]. [tex]\boxed{48}=w[/tex]
[tex]\text{Hello there!}\\\\\text{In this question, we're trying to find the width}\\\\\text{We can find the width with the given information from the question}\\\\\text{We know that the ratio for length to with is 5:4, respectively.}\\\\\text{We also know that the length of the rectangle is 60}\\\\\text{We need to get from5 to 60 in the ratio, so we would multiply}\\\text{by 12}\\\\\text{Now, we would multiply 4 by 12, since whatever you do to the left, you}\\\text{do to the right}\\\\4*12=48[/tex]
[tex]\text{The ratio would be 60:48}\\\\\text{The width of the rectangle is 48 inches}\\\\\large\boxed{\text{Width}=48\,\text{ inches}}\\\\\text{I hope this helps!}\\\text{Best regards,}\\\text{MasterInvestor}[/tex]
