Answer:
The large beaker is 19/60 filled with mixed of salt and fresh water ⇒ E
Step-by-step explanation:
* Lets explain the information to solve the problem
- A small beaker is 1/3 filled with salt water
- A large beaker has five times the capacity of the small beaker
- The large beaker is 1/4 filled with fresh water
- All of the salt water is dumping from the small beaker into the
large beaker
- We need to find to what fraction of its capacity the large beaker
will be filled
* At first lets find the the small beaker is how many times the
large beaker
∵ The capacity of large beaker is 5 times the capacity of the
small beaker
∴ The capacity of the small beaker = 1/5 the capacity of the
large beaker
- Now lets calculate the fraction of the quantity of salt water in
the large beaker
∵ The small beaker is 1/3 filled with salt water
∴ The fraction of the salt water in the large beaker = 1/3 × 1/5 = 1/15
- Lets add the quantities of the salt water and the fresh water
∵ The large beaker is 1/4 filled with fresh water
∴ The the fraction of the two quantities = [tex]\frac{1}{4}+\frac{1}{15}[/tex]
∵ The lowest common factor of 4 and 15 is 60
∴ [tex]\frac{1(15)}{60}+\frac{1(4)}{60}[/tex]
∴ [tex]\frac{15}{60}+\frac{4}{60}[/tex] = [tex]\frac{19}{60}[/tex]
∴ The large beaker is 19/60 filled with mixed of salt and fresh water
