Respuesta :
Answer:
Force of repulsion is 4 N.
Explanation:
It is given that,
If separation between the charged sphere, r = 1 cm = 0.01 m
Force of repulsion, F = 16 N
We need to find the force of repulsion (F') when the separation between the spheres is r' = 2 cm = 0.02 m
The force of attraction or repulsion is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
i.e. [tex]F\propto \dfrac{1}{r^2}[/tex]
So, [tex]\dfrac{F}{F'}=\dfrac{r'^2}{r^2}[/tex]
[tex]\dfrac{16}{F'}=\dfrac{0.02^2}{0.01^2}[/tex]
F' = 4 N
So, the force of repulsion between the spheres is 4 N when the separation is 2 cm. Hence, this is the required solution.
Answer:
4 N is the mutual force of repulsion between two charged spheres 2 cm apart if the repulsive force for a 1 cm separation is 16 N.
