Respuesta :
Answer : The net ionic equation will be,
(a) [tex]C_2O_4^{2-}(aq)+Ba^{2+}(aq)\rightarrow BaC_2O_2(s)[/tex]
(b) [tex]Pb^{2+}(aq)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)[/tex]
(c) [tex]CaCO_3(s)+2H^+(aq)\rightarrow CO_2(g)+Ca^{2+}(aq)+H_2O(l)[/tex]
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a) The given balanced ionic equation will be,
[tex]K_2C_2O_4(aq)+Ba(OH)_2(aq)\rightarrow 2KOH(aq)+BaC_2O_2(s)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]2K^+(aq)+C_2O_4^{2-}(aq)+Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow BaC_2O_2(s)+2K^+(aq)+2OH^{-}(aq)[/tex]
In this equation, [tex]K^+\text{ and }OH^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]C_2O_4^{2-}(aq)+Ba^{2+}(aq)\rightarrow BaC_2O_2(s)[/tex]
(b) The given balanced ionic equation will be,
[tex]Pb(NO_3)_2(aq)+H_2SO_4(aq)\rightarrow 2HNO_3(aq)+PbSO_4(s)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]Pb^{2+}(aq)+2NO_3^{-}(aq)+2H^{+}(aq)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)+2H^+(aq)+2NO_3^{-}(aq)[/tex]
In this equation, [tex]H^+\text{ and }NO_3^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Pb^{2+}(aq)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)[/tex]
(c) The given balanced ionic equation will be,
[tex]CaCO_3(s)+H_2SO_4(aq)\rightarrow CO_2(g)+CaSO_4(aq)+H_2O(l)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]CaCO_3(s)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow CO_2(g)+Ca^{2+}(aq)+SO_4^{2-}(aq)+H_2O(l)[/tex]
In this equation, [tex]SO_4^{2-}[/tex] is the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.The net ionic equation will be,
[tex]CaCO_3(s)+2H^+(aq)\rightarrow CO_2(g)+Ca^{2+}(aq)+H_2O(l)[/tex]
Answer:
As given in the problem statement The complete net ionic equations are following
2KOH =k+OH-
H2SO4=H+SO4 2-
