Answer:
91
Step-by-step explanation:
Given that there are three digit positive integers whose three digits are all different and nonzero
Since it is given as odd integers and greater than 700,
we have the numbers of the form
with first digit >6, last digit any one of 1,3,5,7,9 alone
Thus we can select first digit in 4 ways.
If first digit is 7, then unit digit has only 4 choices excluding 7, and second digit 7 ways. Thus starting with 7 = 28 numbers
Starting with 8:
Unit digit can be any one of the five odd, and second digit 7 ways
No of digits = 35
Similarly for 9, we get 28.
Hence total numbers that can be formed that are odd and >700 are
[tex]28+35+28\\=91[/tex]
