Explanation:
As molarity is the number of moles placed in a liter of solution. Therefore, no. of mole = Molarity × volume of solution in liter
Hence, moles of [tex]Cu(NO_{3})_{2}[/tex] will be calculated as follows.
No. of mole of [tex]Cu(NO_{3})_{2}[/tex] = [tex]0.3842 M \times 0.04388 L[/tex] = 0.0168 mole
According to the given reaction, 2 mole of [tex]Cu(NO_{3})_{2}[/tex] react with 4 mole of KI.
Therefore, for 0.0168 mole amount of [tex]Cu(NO_{3})_{2}[/tex] required will be as follows.
[tex]Cu(NO_{3})_{2}[/tex] = [tex]0.0168 \times \frac{4}{2}[/tex]
= 0.0337 mole of KI
Hence, volume of KI required will be calculated as follows.
Volume = [tex]\frac{\text{no. of moles}}{Molarity}[/tex]
Volume of KI = [tex]\frac{0.0337}{0.2089}[/tex]
= 0.1614 liter
= 161.4 ml (as 1 L = 1000 mL)
Thus, we can conclude that 161.4 ml volume of a 0.2089 M KI is required for the given situation.
