Respuesta :
Answer:
False
Explanation:
The magnitude of any vector is given by,
[tex]||A||=\sqrt{A_x^2+A_y^2}[/tex]
The magnitude of anything is never negative. It can be even seen from the formula that the components are squared. A squared value can never be negative. Even if the component is negative the square will be always positive.
So, magnitude of the vector is not negative.
Answer:
The given statement is false.
Explanation:
For a given vector [tex]\overrightarrow{A}=A_{x}\widehat{i}+A_{y}\widehat{j}[/tex]
The magnitude is given by [tex]|A|=\sqrt{A_{x}^{2}+A_{y}^{2}}[/tex]
As we can see that the quantity on the right side of equation is always positive since square root of a quantity is always positive thus we conclude that the magnitude of any vector and hence vector A is always positive.
