Answer:
1.04 tonnes
Explanation:
As we have the equation balanced, we need to know, form the percent yield and the theoretical yield, the actual yield:
[tex]\% yield=\frac{actual}{theoretical} *100\\\\actual=\frac{\% yield*theoretical}{100} \\\\actual=\frac{92.30*2}{100} \\\\actual=1.846[/tex]
With this, we need to convert the mass of sucrose into moles:
[tex]M_{sucrose}=342.3g/mole\\m_{sucrose}=10^{6}g\\n_{sucrose}=2921.41 moles[/tex]
Now, with the yield, we apply the rule of three, with the actual yield, to know the moles of citric acid produced:
[tex]1mole\longrightarrow 1.846mole\\2921.41mole \longrightarrow x\\\\x=2921.41*1.846=5392.93mole[/tex]
Therefore, 5392.93 moles of citric acid are produced, now we need to know the mass:
[tex]M_{citric}=192.12g/mole\\n_{citric}=5392.93mole\\m_{citric}=1.04x10^{6}g\\m_{citric}=1.04tonnes[/tex]
