Answer: The final temperature of water is 38.5°C
Explanation:
To calculate the amount of heat released or absorbed, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat absorbed = 1.506 kJ = 1506 J (Conversion factor: 1 kJ = 1000 J)
m = mass of water = 30 g
c = specific heat capacity of water = 4.184 Jl/g.°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=T_2-26.5^oC[/tex]
Putting values in above equation, we get:
[tex]1506J=30g\times 4.184J/g.^oC\times (T_2-26.5^oC)\\\\T_2=38.5^oC[/tex]
Hence, the final temperature of water is 38.5°C
