Answer:
The correct answer is option C.
Explanation:
Half life for second order kinetics is given by:
[tex]t_{\frac{1}{2}=\frac{1}{k\times A_0}[/tex]
[tex]t_{\frac{1}{2}[/tex] = half life = 15.4 s
k = rate constant =?
[tex]A_0[/tex] = initial concentration = 0.67 M
[tex]15.4 s=\frac{1}{k\times 0.67 M}[/tex]
[tex]k=\frac{1}{15.4 s\times 0.67 M}=0.09692 M^{-1} s^{-1}=9.69\times 10^{-2}M^{-1} s^{-1}\approx 9.7\times 10^{-2} M^{-1} s^{-1}[/tex]
[tex]9.7\times 10^{-2} M^{-1} s^{-1}[/tex] is the rate constant for this reaction.
