Answer:
[tex]b=\pm2\sqrt{2}[/tex]
Step-by-step explanation:
For the spring mass system
my"+by'+ky=0
The system is said to be critically damped if [tex]b^2-4mk=0[/tex]
Here b is coefficient of friction
m is the mass of system
And k is spring constant
We have given m = 2 kg , k =1
So [tex]b^2-4\times 2\times 1=0[/tex]
[tex]b^2=8[/tex]
[tex]b=\pm2\sqrt{2}[/tex]
So the coefficient of friction is [tex]\pm2\sqrt{2}[/tex]
