Answer:
[tex]\boxed{\text{131.3 kJ/mol}}[/tex]
Explanation:
The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is
[tex]\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})[/tex]
C(s) + H₂O(g) ⇌ CO(g) + H₂(g)
ΔH°f/kJ·mol⁻¹: 0 -241.8 -110.5 0
[tex]\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & -110.5 - (-241.8)\\& = & -110.5 + 241.8\\& = & \textbf{131.3 kJ/mol}\\\end{array}\\\text{The enthalpy of reaction is }\boxed{\textbf{131.3 kJ/mol}}[/tex]
