Answer: The pH of the solution is 9.71
Explanation:
1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.
We are given:
pOH of the solution = 7.2
To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOh of the solution, we use the equation:
[tex]pOH=-\log[OH^-][/tex]
We are given:
[tex][OH^-]=5.09\times 10^{-5}M[/tex]
Putting values in above equation, we get:
[tex]pOH=-\log(5.09\times 10^{-5})\\\\pOH=4.29[/tex]
To calculate pH of the solution, we use the equation:
[tex]pH+pOH=14\\pH=14-4.29=9.71[/tex]
Hence, the pH of the solution is 9.71
