contestada

In a Cavendish experiment that first measured gravity, a 0.730 kg lead ball was placed 0.230 m away from a 158 kg lead ball. How much gravitational force did that create?

Respuesta :

Answer: [tex]1.45(10)^{-7} N[/tex]

Explanation:

According to Newton's law of Gravitation, the force [tex]F[/tex] exerted between two bodies of masses [tex]m1[/tex] and [tex]m2[/tex]  and separated by a distance [tex]r[/tex]  is equal to the product of their masses and inversely proportional to the square of the distance:

[tex]F=G\frac{(m1)(m2)}{r^2}[/tex]

Where:

[tex]G=6.674x10^{-11}\frac{m^{3}}{kgs^{2}}[/tex]is the gravitational constant, which was thanks to Cavendish experiment

[tex]m1=0.730 kg[/tex]

[tex]m2=158 kg[/tex]

[tex]r=0.230 m[/tex]

[tex]F=6.674x10^{-11}\frac{m^{3}}{kgs^{2}}\frac{(0.730 kg)(158 kg)}{(0.230 m)^2}[/tex]

Solving:

[tex]F=0.000000145 N= 1.45(10)^{-7} N[/tex]

Answer:

Coefficient: 1.45 (enter the answer in proper scientific notation)

Exponent: -7

Explanation:

Coefficient must be between 1 and 10