An airline has classified its customers as high-volume travelers (assumed to be business travelers) or low-volume travelers (assumed to be leisure travelers). Eight-five (85) percent are high volume travelers. If five people are randomly selected from a list of customers, what is the probability all are high-volume (business) travelers?

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Answer:

The probability is 44.37%.

Step-by-step explanation:

The probability for a given customer to belong to the business class is given by:

[tex]P(B)=0.85[/tex]

Since each event is independent we'll obtain the probability as follows:

[tex]P(BBBBB) = P(B)\times P(B) \times P(B)\times P(B)\times P(B)= 0.85^5=0.4437[/tex]

Therefore the probability that 5 customers chosen from a randomly selected list of customers all belong to the business class is of 44.37%.

Answer:

The probability that the 5 travelers chosen are high volume travelers is 0.4437

Step-by-step explanation:

The number of people who are high volume travelers, in the random sample of 5 people, is a binomial random variable [tex] X [/tex] with probability of success [tex] p = 0.85 [/tex], [tex] n = 5 [/tex]. Therefore, the model is [tex] {5 \choose x} (0.85)^{x}(0.15)^{(5-x)} [/tex]. So, you have:

[tex] P (X = 5) = {5 \choose 5}(0.85)^{5}(0.15)^{0} = 0.4437 [/tex].

The probability that the 5 travelers chosen are high volume travelers is 0.4437