Answer: [tex]x(6-x)[/tex]
Step-by-step explanation:
Given : Two opposite sides of a rectangle are each of length x.
Let the other adjacent side be y.
The perimeter of the rectangle is 12 units.
Perimeter of rectangle is given by :-
[tex]P=2(\text{Sum of adjacent sides})\\\\\Rightarrow\ 12=2(x+y)\\\\\Rightarrow\ x+y=\dfrac{12}{2}=6\\\\\Rightarriow\ y=6-x[/tex]
The area of rectangle is given by :-
[tex]A=\text{product of two adjacent sides}\\\\\Rightarrow\ A=xy=x(6-x)[/tex]
Hence, the area as a function x = [tex]x(6-x)[/tex]
Answer:
option B
Step-by-step explanation:
given,
two opposite side of rectangle of each length = x
perimeter of the rectangle = 12
let the unknown sides be y
perimeter of the rectangle
2 x + 2 y = 12
y = 6 -x
hence, we know area of the triangle will be (length × breadth)
= x × y
= x × ( 6 - x )
so, area of rectangle will be x(6-x) correct answer will be option B
