In a population that is in Hardy-Weinberg equilibrium, 64% of the individuals express the recessive phenotype for a particular gene locus. What is the expected frequency of the recessive allele in this population?

Respuesta :

Answer:

Expected frequency of the recessive allele in this population [tex]= 80[/tex]%

Explanation:

Given -

Recessive phenotype expressed by an individuals for a particular gene locus is [tex]64[/tex]%

Now as per Hardy-Weinberg equilibrium equation, the frequency of individual with recessive phenotype is represented by "[tex]q^{2}[/tex]"

where "q" is the frequency for recessive allele.

Thus,

q [tex]= \sqrt{q^2} \\= \sqrt{0.64} \\= 0.8\\[/tex]

Expected frequency of the recessive allele in this population [tex]= 80[/tex]%