Answer:
Option D , [tex]0.43[/tex]
Explanation:
Given -
Frequency of individuals that are resistant (rr) is [tex]0.22[/tex] represented as "[tex]q^2[/tex]"
Frequency of individual that are not resistant with homozygous dominant genotype (RR) is [tex]0.36[/tex] represented as "[tex]p^2[/tex]"
Frequency of individual that are not resistant with heterozygous (Rr) genotype is [tex]0.42[/tex] represented as "[tex]pq[/tex]"
As per Hardy Weinberg equation , at equilibrium-
[tex]p^2+q^2+2pq = 1\\0.36+0.22+0.42 = 1[/tex]
Thus, the given population follow hardy Weinberg equilibrium.
Thus, frequency of the r allele in the population is equal to
[tex]\sqrt{q^2} \\= \sqrt{0.22}\\ = 0.469[/tex]
The nearest value to this frequency is option D
Hence option D is correct.
