Which of the following compounds will have the highest molar solubility in pure water? Which of the following compounds will have the highest molar solubility in pure water? Ag2S, Ksp=6.0×10−51 ZnS, Ksp=2.0×10−25 Fe(OH)3, Ksp =2.79×10−39 ZnSe, Ksp=3.6×10−26 PbS, Ksp=9.04×10−29

Respuesta :

Answer:

Zinc sulfide, ZnS.

Explanation:

Hello,

In general, the solubility product is obtained via the shown below widespread expression for a random highly insoluble solid:

[tex]CA(s)-->C^+(aq)+A^-(aq)[/tex]

Whereas [tex]C[/tex] and [tex]A[/tex] stand for random cationic and anionic arbitrary species, therefore the law of mass action becomes:

[tex]Ksp=[C^+]_{eq}[A^-]_{eq}[/tex]

In such a way, one state that the compound having the highest solubility is the one that has the higher solubility product constant, that is zinc sulfide (ZnS) which has the following constant:

[tex]Ksp_{ZnS}=2.0x10^{-25}[/tex]

Best regards.

The molar solubility has been the moles of solute dissolved in the liter of solution. The highest molar solubility in pure water is of ZnS.

What is solubility equilibrium?

The solubility equilibrium has been the product of the ions for the solubility of the compound. The solubility product has been given as Ksp.

The higher the solubility product, the more number of ion are produced from the compound, and higher will be the solubility.

The highest Ksp among the given compounds is of ZnS. Thus, the highest molar solubility in pure water is of ZnS. Hence, option B is correct.

Learn more about solubility equilibrium, here:

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