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Mrs.Allans car uses 8 gallons of gas for a 224-mile trip. Mrs.Owens car uses 6 gallons of gas for a 210-mile trip.

PartA: What are the unit rates for each cars gas usage?
PartB: Whose car has better gas mileage?

PartC: At these rates, how many gallons of gas would each car use if both cars traveled 560 miles? Explain

Answer what you can please. It is appreciated

MrsAllans car uses 8 gallons of gas for a 224mile trip MrsOwens car uses 6 gallons of gas for a 210mile trip PartA What are the unit rates for each cars gas usa class=
MrsAllans car uses 8 gallons of gas for a 224mile trip MrsOwens car uses 6 gallons of gas for a 210mile trip PartA What are the unit rates for each cars gas usa class=

Respuesta :

Cricetus

Answer:

A. Mileage is read in Miles per gallons

B.Hence ownens car has a better mileage

C. Allans CAr : 20 gallons

Owens car : 16 Gallons

Step-by-step explanation:

Allans Car

Distance traveled  = 224 miles

Fuel consumed = 8 gallons

Distance covered in 1 gallon = [tex]\frac{224}{8}[/tex] = 28

Hence mileage is 28 miles per gallon

Owens Car

Distance traveled  = 210 miles

Fuel consumed = 6 gallons

Distance covered in 1 gallon = [tex]\frac{210}{6}[/tex]  = 35

Hence mileage is 35 miles per gallon

Hence ownens car has a better mileage

If the Distance traveled by both car is 560 miles

Allans car

Fuel consumed =  [tex] \frac{560}{28}[/tex]   = 20 gallons

Owens car

Fuel consumed =  [tex] \frac{560}{35}[/tex]   = 16 gallons

lublana

Answer:

A.Rate of Mrs. Allan's car=28 mile/gallon

Rate of Mrs. Owen's car=35 mile/gallon

B.Mrs. Owen's car

C.Mrs.Allen's car  used gas for 560 miles=20 gallons

Mrs.Owen's car used gas for 560 miles=16 gallons

Step-by-step explanation:

We are given that

Mrs. Allan's car uses 8 gallons of gas for 224 mile tripe.

Mrs. Owens car uses 6 gallons of a gas for 210 mile tripe.

A.Rate=[tex]\frac{Distance\;traveled}{Gas;used}[/tex]

Rate of Mrs. Allan's car=[tex]\frac{224}{8}=28 mile/gallon[/tex]

Rate of Mrs. Owen's car=[tex]\frac{210}{6}=35 mile/gallon[/tex]

B.Mrs.Allan's car travel in 1 gallon of gas =28 miles

Mrs. Owen' s car travel in one gallon of gas=35 miles

Therefore, Mrs. Owen's car travel large distance in one gallon of gas.Hence, it is better.

C.If distance traveled by the cars=560 miles

Mrs. Allen's car used gas for 28 mile=1 gallon

Mrs. Allen's car used gas for 1 mile=[tex]\frac{1}{28}[/tex]

Mrs.Allen's car  used gas for 560 mile=[tex]\frac{560}{28}=20 gallons[/tex]

Mrs.Allen's car  used gas for 560 miles=20 gallons

Mrs.Owen's car used gas for 35 miles=1 gallon

Mrs. Owen's car used gas for 1 mile=[tex]\frac{1}{35}[/tex]

Mrs. Owen's car used gas for 560 miles=[tex]\frac{560}{35}=16 gallons[/tex]

Mrs.Owen's car used gas for 560 miles=16 gallons

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