Respuesta :
Answer:
Minimum amount of [tex]NaHCO_3[/tex] = 6.88 g
Explanation:
Benzoic acid reacts with [tex]NaHCO_3[/tex] as:
[tex]C_6H_5COOH + NaHCO_3 \rightarrow C_6H_5COONa + CO_2 + H_2O[/tex]
Molar mass of [tex]C_6H_5COOH[/tex] = 122 g/mol
Molar mass of [tex]NaHCO_3[/tex]=84 g/mol
No. of moles of [tex]C_6H_5COOH[/tex] = [tex]\frac{10}{122} mol [/tex]
From reaction,
1 mol of [tex]C_6H_5COOH[/tex] reacts with 1 mol of [tex]NaHCO_3[/tex]
[tex]\frac{10}{122} mol [/tex] mol of [tex]C_6H_5COOH[/tex] will react with
= [tex]\frac{10}{122} mol [/tex] of [tex]NaHCO_3[/tex]
Mass of [tex]NaHCO_3[/tex] in g = No. of mol × Molar mass
= [tex]=\frac{10}{122} \times 84 = 6.88\ g[/tex]
