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The barometer of a mountain hiker reads 750 mbars at the beginning of a hiking trip and 650 mbars at the end. Neglecting the effect of altitude on local gravitational acceleration, determine the vertical distance climbed. Assume an average air density of 1.35 kg/m3.

Respuesta :

Answer:

755.1 m

Explanation:

Initial pressure = 750 mbar

Final pressure = 650 mbar

Converting to Pascal

1 mbar = 100 Pa

Initial pressure = 750 mbar = 75000 Pa

Final pressure = 650 mbar = 65000 Pa

ΔP = Pressure difference = 75000-65000 = 10000 Pa

g = Acceleration due to gravity = 9.81 m/s²

Δh = Height difference

ρ = Density of air = 1.35 kg/m³

ΔP = ρgΔh

[tex]\Delta h=\frac{\Delta P}{\rho g}\\\Rightarrow \Delta h=\frac{10000}{1.35\times 9.81}\\\Rightarrow \Delta h=755.1\ m[/tex]

∴ Vertical distance climbed is 755.1 m

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