An object having a net charge of 25.0 µC is placed in a uniform electric field of 620 N/C directed vertically. What is the mass of this object if it "floats" in the field?

Respuesta :

Answer:

Mass of the object, [tex]m=1.58\times 10^{-3}\ kg[/tex]

Explanation:

It is given that,

Charge on an object, [tex]q=25\ \mu C=25\times 10^{-6}\ C[/tex]

Electric field, E = 620 N/C

We need to find the mass of this object. Let m is the mass of the object. It can be calculated as :

[tex]ma=qE[/tex]

[tex]m=\dfrac{qE}{a}[/tex], here a = g (as it is vertically downward)

[tex]m=\dfrac{25\times 10^{-6}\times 620}{9.8}[/tex]

m = 0.00158 kg

[tex]m=1.58\times 10^{-3}\ kg[/tex]

So, the mass of the object is [tex]1.58\times 10^{-3}\ kg[/tex]. Hence, this is the required solution.