Answer:
It will require 33 days to reach concentration of the chemical equal to 0.14 mg/ L
Explanation:
For a first order reaction : [tex]A\rightarrow product[/tex]
The rate law is - [tex]ln[\frac{[A]_{0}}{[A]_{t}}]=kt[/tex]
Where [tex][A]_{0}[/tex] and [tex][A]_{t}[/tex] are initial concentration of A and concentration of A after t time respectively. k is degradation constant or rate constant.
Here k = 0.2 [tex]day^{-1}[/tex] , [tex][A]_{0}=100.0 mg/L[/tex] and [tex][A]_{t}=0.14 mg/L[/tex]
So plug-in all the given values in the rate equation-
[tex]ln[\frac{100.0}{0.14}]=0.2\times t[/tex]
or, t = 33
So, it will require 33 days to reach concentration of the chemical equal to 0.14 mg/ L
