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The concentration determined for an unknown sample of hydrochloric acid by a student is 0.1355 M. According to the instructor’s information, the true molarity (M) of this solution is 0.1364 M. What is the percent error in this experiment?

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hmorcella

Answer:

The percentage of error in this experiment is 0.66%

Step-by-step explanation:

The value measured by a student, let's call it [tex]xm[/tex], is equal to 0.1355 M. And the real value of molarity is,let's call it [tex]xr[/tex] is equal to 0.1364.

The error in the measurement (E) is equal to the absolute difference between the real value and the measured value:

abs ( xr - xm ) = E

So in this experiment it will be equal to:

abs ( 0.1364 - 0.1355 ) = 0.0009

And the percentage of error (e) will be:

[tex]e = \frac{E}{xr}*100[/tex]

Thus,

e = 0.0009 * 100 / 0.1364  ⇒ e= 0.659 % ≈ 0.66 %

So, the percentage of error in this experiment is 0.66%

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