Answer:
[tex]8x^{3}-34x^{2}+25x-3[/tex]
Step-by-step explanation:
In order to solve this problem, lets take the two terms in the binomial (4x and -3) and, for each one, multiply them by each term in the trinomial (2x^2, -7x, and 1):
[tex](4x-3)(2x^{2}-7x+1)[/tex]
[tex](4x*2x^{2})+(4x*-7x)+(4x*1)+(-3*2x^{2})+(-3*-7x)+(-3*1)[/tex]
[tex]8x^{3}+(-28x^{2})+4x+(-6x^{2})+21x+(-3)\\[/tex]
[tex]8x^{3}-28x^{2}+4x-6x^{2}+21x-3[/tex]
Let's combine like terms to get our final answer:
[tex]8x^{3}-28x^{2}-6x^{2}+4x+21x-3[/tex]
[tex]8x^{3}-34x^{2}+25x-3[/tex]
