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On a coordinate plane, a line goes through (negative 3, 2) and (0, 1). A point is at (3, 4). What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)? y = –One-thirdx + 5 y = –One-thirdx + 3 y = 3x + 2 y = 3x − 5

Respuesta :

calculista

Answer:

[tex]y=3x-5[/tex]

Step-by-step explanation:

step 1

Find the slope of the given line

we have

(-3,2) and (0,1)

The slope m is

[tex]m=(1-2)/(0+3)=-1/3[/tex]

step 2

Find the slope of the line perpendicular to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of its slopes is -1)

so

The slope is

[tex]m=3[/tex]

step 3

Find the equation of the line in point slope form

we have

[tex]m=3[/tex]

[tex]point(3,4)[/tex]

[tex]y-4=3(x-3)[/tex] ----> equation in point slope form

Convert to slope intercept form

[tex]y=3x-9+4[/tex]

[tex]y=3x-5[/tex]

Answer:

y=3x - 5

Step-by-step explanation:

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