Answer:
191.67
Explanation:
focal length of objective lens, fo = 0.6 cm
focal length of eyepiece, fe = 2.5 cm
Distance between the lenses, L = 14 cm
Least distance of distinct vision for normal eye, d = 25 cm
The formula for the magnification of the compound microscope is given by
[tex]M =-\frac{\left ( L-f_{e} \right )d}{f_{o}f_{e}}[/tex]
[tex]M =-\frac {\left ( 14-2.5 \right )25}{0.6 \times 2.5}}[/tex]
M = - 191.67
Thus, the magnification of the compound microscope is 191.67.
