Answer:
[tex]F_3=(-12,-11,-10)[/tex]
Explanation:
It is given that,
Force, [tex]F_1=(12,7,2)[/tex]
Force, [tex]F_2=(0,4,8)[/tex]
We need to find the force F₃ that must act on the object so that the sum of the forces is zero. Let [tex]F_3=(x,y,z)[/tex]
According to question, [tex]F_1+F_2+F_3=0[/tex]
[tex](12,7,2)+(0,4,8)+(x,y,z)=0[/tex]
[tex](12+x)+(11+y)+(10+z)=0[/tex]
Since, 12 + x = 0, 11 + y = 0 and 10 + z = 0
The third force is equal to,
[tex]F_3=(-12,-11,-10)[/tex]
Hence, this is the required solution.
