Respuesta :
Answer:
[tex]Fraction\ of\ electrons\ lost=6.82\times 10^{-18}[/tex]
Explanation:
Mass of copper = 50 g
Molar mass of copper = 63.5 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{50\ g}{63.5\ g/mol}[/tex]
[tex]Moles= 0.7874\ mol[/tex]
Also,
1 atom of neutral copper contains 29 electrons
1 mole of neutral copper contains [tex]29\times 6.023\times 10^{23}[/tex] electrons
0.7874 moles of neutral copper contains [tex]29\times 6.023\times 10^{23}\times 0.7874[/tex] electrons
0.7874 moles of neutral copper contains [tex]1.3753\times 10^{25}[/tex] electrons.
Given, Charge = 1.5 μC
1 μ = 10⁻⁶ C
So, Charge on the copper = [tex]1.5\times 10^{-6}\ C[/tex]
Charge on 1 electron = [tex]1.6\times 10^{-19}\ C[/tex]
Thus, number of electrons = Total charge / Charge on one electron
Thus,
[tex]n=\frac {1.5\times 10^{-6}}{1.6\times 10^{-19}}=9.375\times 10^{12}[/tex]
Fraction :
[tex]Fraction\ of\ electrons\ lost=\frac {9.375\times 10^{12}}{1.3753\times 10^{25}}=6.82\times 10^{-18}[/tex]
