CuSO4 absorbs light strongly at a wavelength of 635 nm. Consider that you measure the initial intensity of light, Io, entering the solution at 635 nm, and the intensity of light passing through the solution, I, at 635 nm. Sample 1: 0.400 M CuSO4 Sample 2: 0.200 M CuSO4 Which of the following statements is true? Group of answer choices The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2. The percent transmittance of light, %T, will be the same for Sample 1 compared to Sample 2. The percent transmittance of light, %T, will be lower for Sample 1 compared to Sample 2.

Question

01-10-2019
Chemistry

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CuSO4 absorbs light strongly at a wavelength of 635 nm. Consider that you measure the initial intensity of light, Io, entering the solution at 635 nm, and the intensity of light passing through the solution, I, at 635 nm. Sample 1: 0.400 M CuSO4 Sample 2: 0.200 M CuSO4 Which of the following statements is true? Group of answer choices The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2. The percent transmittance of light, %T, will be the same for Sample 1 compared to Sample 2. The percent transmittance of light, %T, will be lower for Sample 1 compared to Sample 2.

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fgschem fgschem · Answer 1 · 2019-10-01T16:11:36+02:00

Answer:

The right statement is "The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2."

Explanation:

The Beer-Lambert Law states that the absorbance is directly proportional to the concentration of the substance.

Absorbance = εLc

ε: molar absorptivity coeficient

L: optical path length

c: molar concentration

Therefore, if ε and L are the same, the higher the concentration, the higher the absorbance and the lower the transmitance.

Since sample 1 has a higher concentration of CuSO₄ than sample 2, sample 1 has a higher absorbance and lower percent transmittance.

dsdrajlin dsdrajlin · Answer 2 · 2021-10-18T00:04:38+02:00

When light passes through to samples of CuSO₄, the percent transmittance of light, %T, will be lower for Sample 1 compared to Sample 2.

CuSO₄ absorbs light strongly at a wavelength of 635 nm. We can measure this process through 2 variables closely related:

Absorbance: is a measure of the quantity of light absorbed by a sample.
Transmittance: is the ratio of the light passing through to the light incident on the sample.

We can relate the absorbance (A) of a sample to its concentration (c) through Lambert-Beer's law.

[tex]A = \epsilon \times l \times c[/tex]

where,

ε: molar absorptivity of the species
l: length of light path

We can see from this expression, that there is a direct relationship between concentration and absorbance. Thus, sample 1, with a higher concentration, will have a higher absorbance.

On the other hand, we can relate absorbance to percent transmittance (%T) through the following expression.

[tex]\% T = 10^{2-A}[/tex]

As we can see, there is an inverse relationship between absorbance and percent transmittance. Thus, sample 1, with a higher absorbance, will have a lower percent transmittance.

When light passes through to samples of CuSO₄, the percent transmittance of light, %T, will be lower for Sample 1 compared to Sample 2.

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